Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Mid-Chapter Check Point - Page 71: 39

Answer

$-x^{3}$

Work Step by Step

If $x$ is positive, then $|x|=x$, if $x$ is negative, then $|x|=-x.$ Thus $ x^{2}|x|=-x^{2}x^{1}\qquad$... apply $a^{m}a^{n}=a^{m+n}$ =$-x^{3}$
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