Answer
$7\sqrt{5}+14$
Work Step by Step
Use $(a+b)(a-b)=a^{2}-b^{2}\quad$ when rationalizing.
$[(a+\sqrt{b})(a-\sqrt{b})=a^{2}-b]$
$\displaystyle \frac{7}{\sqrt{5}-2}\cdot\frac{\sqrt{5}+2}{\sqrt{5}+2}=\frac{7(\sqrt{5}+2)}{5-4}\\\\\\=\dfrac{7(\sqrt{5}+2)}{1}=7\sqrt{5}+14$
