Answer
$-\dfrac{1}{2}$
Work Step by Step
RECALL:
(i) $\sqrt[n]{a^n}=a$ when $n$ is odd.
(ii) $\sqrt[n]{a^n}=|a|$ when $n$ is even.
Write the radicand in exponential form (as a fifth power) to obtain
$\sqrt[5]{\left(-\dfrac{1}{2}\right)^5}.$
Use rule (i) above to obtain
$\sqrt[5]{\left(-\dfrac{1}{2}\right)^5} = -\dfrac{1}{2}.$
