Answer
$2x$
Work Step by Step
Using the properties of radicals and exponents, the given expression simplifies to
$\sqrt[5]{\dfrac{64x^6}{2x}}
\\=\sqrt[5]{32x^{6-1}}
\\=\sqrt[5]{32x^5}
\\=\sqrt[5]{2^5x^5}
\\=\sqrt[5]{(2x)^5}
\\=2x.$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 45: 73
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