Answer
$9r+4$
Work Step by Step
Step 1. Rewrite and factor the numerator as $72r^2+59r+12=72r^2+27r-27r+59r+12=9r(8r+3)+32r+12=9r(8r+3)+4(8r+3)=(8r+3)(9r+4)$
Step 2. We have $\frac{72r^2+59r+12}{8r+3}=\frac{(8r+3)(9r+4)}{8r+3}=9r+4$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 83: 60
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