Answer
$(13y^2+1)(13y^2-1)$
Work Step by Step
Use the formula $A^2-B^2=(A+B)(A-B)$, we have $169y^4-1=(13y^2)^2-1^2=(13y^2+1)(13y^2-1)$
optional: $(13y^2+1)(13y^2-1)=(13y^2+1)(\sqrt {13}y+1)(\sqrt {13}y-1)$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 83: 70
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