Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 83: 81

Answer

$\frac{p+6q}{p+q}$

Work Step by Step

Factor each part: $p^{2}-36q^{2} = (p+6q)(p-6q)$ $p^{2}-12pq+36q^{2} = (p-6q)(p-6q)$ $p^{2}-5pq-6q^{2}=(p-6q)(p+q)$ $p^{2}+2pq+q^{2}=(p+q)(p+q)$ Now you have: $\frac{ (p+6q)(p-6q)}{(p-6q)(p-6q)}\times\frac{(p-6q)(p+q)}{(p+q)(p+q)}$ Cancel and simplify $$\frac{p+6q}{p+q}$$
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