Answer
$(0,1)$ and $(-1,0)$ are on the graph.
$(1,2)$ is not on the graph.
Work Step by Step
For a point to be on the graph, it must satisfy the equation.
Therefore we have to see for all three of the points if they satisfy the given equation: $y^3=x+1$.
This can be don by substituting the values of $x$ and $y$ iof each point nto the equation.
For the first point:
$y^3=2^3=8$
$x+1=1+1=2$
$8\ne2$
Thus, the point is not on the graph.
For the second point:
$y^3=1^3=1$
$x+1=0+1=1$
$1=1$
Thus, the point is on the graph.
For the third point:
$y^3=0^3=0$
$x+1=-1+1=0$
$0=0$
Thus, the point is on the graph.
