Answer
$(-2,2)$ is not on the graph.
$(0,2)$ and $(\sqrt2,\sqrt2)$ are on the graph
Work Step by Step
The points that are on the graph must satisfy the equation.
Therefore we have to see for all three of the points if they satisfy the given equation: $x^2+y^2=4$
For the first point:
Left side: $x^2+y^2=0^2+2^2=4$
Right side: $4$
$4=4$
The point is on the graph.
For the second point:
Left side: $x^2+y^2=(-2)^2+2^2=8$
Right side: $4$
$8\ne4$
The point is not on the graph.
For the third point:
Left side: $x^2+y^2=\sqrt2^2+\sqrt22^2=4$
Right side: $4$
$4=4$
The point is on the graph.
