Answer
There are two x-intercepts: $-1$ and $1$ .
The y-intercept is $-1$ .
See the graph below.
Work Step by Step
In order to find the $x$-intercept, we have to plug $y=0$ into the equation, and the $x$-coordinate will give us the intercept itself.
$y=x^2-1$
$0=x^2-1$
$x^2=1$
$x=\pm1$
The same thing should be done for the $y$-intercept, however, here $x=0$ should be plugged into the equation.
$y=x^2-1$
$y=0^2-1$
$y=-1$
There are two $x$-intercepts: $-1$ and $1$.
The $y$-intercept is $-1$
Few other points that will help us plot the graph:
If $x=0$
$y=0^2-1=-1$
The point $(0,-1)$ is on the graph.
If $x=-2$
$y=(-2)^2-1=3$
The point $(-2,3)$ is on the graph.
If $x=2$
$y=2^2-1=3$
The point $(2,3)$ is on the graph.
