Answer
The $x$-intercepts are $1$ and $-1$
The y-intercept is $4$
See the graph below.
Work Step by Step
In order to find the $x$-intercept, we have to plug $y=0$ into the equation and solve for $x$,.
$4x^2+y=4$
$4x^2+0=4$
$4x^2=4$
$x^2=1$
$x=\pm1$
The same thing should be done for the $y$-intercept, however, here $x=0$ should be plugged into the equation then solve for $y$.
$4x^2+y=4$
$4(0)^2+y=4$
$y=4$
There are two $x$-intercepts: $1$ and $-1$
The $y$-intercept is $4$
Few other points that will help us plot the graph:
If $x=-2$
$4(-2)^2+y=4$
$y=-12$
The point $(-2,-12)$ is on the graph.
If $x=2$
$4(2)^2+y=4$
$y=-12$
The point $(2,-12)$ is on the graph.
Plot the points and connect them using a smooth curve to complete the graph.
Refer to the graph above.
