Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.3 Lines - F.3 Assess Your Understanding - Page 30: 37

Answer

$y=\dfrac{1}{2}x$

Work Step by Step

The equation of a line can be represented as: $y-y_1=m(x-x_1)$ where $m$ is the slope and $(x_1, y_1)$ is a point on the line. The slope $m$ of the line through the points $(x_1,y_1)$ and $(x_2,y_2)$ can be calculated using the formula: $m=\dfrac{y_2-y_1}{x_2-x_1}$ Plug in the $x$ and $y$ values of the two given points into the formula above to obtain: $m=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1-0}{2-0}=\dfrac{1}{2}$ Thus, with a slope of $\frac{1}{2}$ and the point $(0, 0)$, the equation of the line is: $y-0=\dfrac{1}{2}(x-0) \implies y=\dfrac{1}{2}x$
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