Answer
$y=-\dfrac{2}{3}x-\dfrac{1}{3}$
Work Step by Step
The equation of a line in the point-slope form is the following:
$y-y_1=m(x-x_1)$, where $m$ is the slope and the point $(x_1,y_1)$ is on the graph.
Here, our line's slope is:
$m=-\frac{2}{3}$
Therefore, using the point $(4, -3)$ and the slope $-\frac{2}{3}$, the equation can be written as:
$y-(-1)=-\dfrac{2}{3}(x-1)$
$y+1=-\dfrac{2}{3}(x-1)\\
y+1=-\dfrac{2}{3}x+\dfrac{2}{3}\\
y=-\dfrac{2}{3}x+\dfrac{2}{3}-1\\
y=-\dfrac{2}{3}x-\dfrac{1}{3}
$
