Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.3 Lines - F.3 Assess Your Understanding - Page 30: 60

Answer

$y = -3x - 1$

Work Step by Step

First, let's find the slope of the line given. This line is written in slope-intercept form, which is given by the following formula: $y = mx + b$, where $m$ is the slope of the line and $b$ is the y-intercept. So the slope of this line is the coefficient of $x$; in this case, the slope of this line is $-3$. Therefore, the slope of the line whose equation we want to find is also $-3$. Let us plug this slope and the point we are given into the point-slope form of the equation, which is given by the formula: $y - y_1 = m(x - x_1)$, where $m$ is the slope of the line and $(x_1, y_1)$ is a point on that line. Let us use the point $(-1, 2)$ to plug into the formula: $$y - 2 = -3(x - (-1))$$ Simplify the equation: $$y - 2 = -3(x + 1)$$ We are asked to give the equation either in standard form or slope-intercept form. Let's rewrite this equation in slope-intercept form. First, we distribute the terms on the right side of the equation: $$y - 2 = -3x - 3$$ Isolate $y$ by adding $2$ to each side of the equation: $$y = -3x - 1$$
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