Answer
$y=\dfrac{1}{5}x+\dfrac{23}{5}$
Work Step by Step
The equation of a line in the point-slope form is the following:
$y-y_1=m(x-x_1)$, where $m$ is the slope and the point $(x_1,y_1)$ is on the graph.
Here, our line's slope can be calculated by the formula:
$m=\dfrac{y_2-y_1}{x_2-x_1}$, where the points $(x_1,y_1)$ and $(x_2,y_2)$ are on the line.
We can plug in the given two points:
$m=\dfrac{5-4}{2-(-3)}=\dfrac{1}{5}$
Using the point $(2, 5)$ and the slope $\frac{1}{5}$, the equation of the line can be written as:
$y-5=\dfrac{1}{5}(x-2)\\
y-5=\dfrac{1}{5}x-\dfrac{2}{5}\\
y=\dfrac{1}{5}x-\dfrac{2}{5}+5\\
y=\dfrac{1}{5}x-\dfrac{2}{5}+\dfrac{25}{5}\\
y=\dfrac{1}{5}x+\dfrac{23}{5}\\
$
