Answer
The $y$-intercept is $2$.
The slope is $-\frac{1}{3}$.
See the graph below.
Work Step by Step
First, we have to get the equation's slope-intercept form, that is $y=mx+b$:
Subtract $\frac{1}{3}x$ from both sides to obtain:
$\frac{1}{3}x+y-\frac{1}{3}x=2-\frac{1}{3}x$
$y=-\frac{1}{3}x+2$
This form of the equation is the slope-intercept form.
In this form, the slope of the line equals to the coefficient of $x$ (which is $m$) and the $y$-intercept equals to the constant $b$.
Therefore in the equation $y=-\frac{1}{3}x+2$:
The $y$-intercept is $2$.
The slope is $m=-\frac{1}{3}$.
In order to graph the line, we have to sketch the $y$-intercept, that is $(0,2)$.
As the slope is $-\frac{1}{3}$, we can find another point that we can also sketch.
The slope is the change in $y$ for every $1$ unit change of $x$.
Thus, a slope of $-\frac{1}{3}$ means a $1$-unit increase in $x$ will result to a $-\frac{1}{3}$-unit increase (or $\frac{1}{3}$-unit decrease) in $y$. This is equivalent to a $-1$ unit decrease in $y$ for a $3$-unit increase in $x$.
Using $(0,2)$ as the starting point and a slope of $-\frac{1}{3}$, the coordinates of another point on the line would be:
$(0+3,2-12)=(3,1)$
Plot the two points then connect them using a straigiht line.
Refer to the graph above,
