Answer
The $y$-intercept is $0$.
The slope is $-\dfrac{3}{2}$.
See the graph below.
Work Step by Step
First, we have to get the equation's slope-intercept form, that is $y=ax+b$.
Isolate $y$ to obtain:
\begin{align*}
3x+2y-3x&=0-3x\\
2y&=-3x\\
\frac{2y}{2}&=\frac{-3x}{2}\\
y&=-\frac{3}{2}x
\end{align*}
This form of the equation is the slope-intercept form.
In this form, the slope of the line equals to the coefficient of $x$ (which is $m$) and the $y$-intercept equals to the constant $b$.
Therefore in the equation $=-\dfrac{3}{2}x$:
The $y$-intercept is $0$.
The slope is $-\dfrac{3}{2}$.
In order to graph the line, we have to sketch the $y$-intercept, that is $(0, 0)$.
As the slope is $-\frac{3}{2}$, we can find another point that we can also sketch.
The slope is the change in $y$ for every $1$ unit change of $x$.
Thus, a slope of $-\frac{3}{2}$ means a $1$-unit increase in $x$ will result to a $-\frac{3}{2}$-unit increase (or $\frac{3}{2}$-unit decrease) in $y$. This is equivalent to a $3$ unit decrease in $y$ for a $2$-unit increase in $x$.
Using $(0, 0)$ as the starting point and a slope of $-\frac{3}{2}$, the coordinates of another point on the line would be:
$(0+2, 0-3)=(2, -3)$
Plot the two points then connect them using a straigiht line.
Refer to the graph above,
