Answer
The $y$-intercept is $-2$.
The slope is $1$.
See the graph below.
Work Step by Step
First, we have to get the equation's slope-intercept form, that is $y=mx+b$:
Isolate $y$ to obtain:
\begin{align*}
x-y-x&=2-x\\
-y&=-x+2\\
(-1)(-y)&=(-1)(-x+2)\\
y&=x-2
\end{align*}
This form of the equation is the slope-intercept form.
In this form, the slope of the line equals to the coefficient of $x$ (which is $m$) and the $y$-intercept equals to the constant $b$.
Therefore in the equation:
The $y$-intercept is $-2$.
The slope is $1$.
In order to graph the line, we have to sketch the $y$-intercept, that is $(0, -2)$.
As the slope is $1$, we can find another point that we can also sketch.
The slope is the change in $y$ for every $1$ unit change of $x$.
Thus, a slope of $1$ means a $1$-unit increase in $x$ will result to a $1$-unit increase in $y$.
Using $(0, -2)$ as the starting point and a slope of $1$, the coordinates of another point on the line would be:
$(0+1, -2+1)=(1, -1)$
Plot the two points then connect them using a straigiht line.
Refer to the graph above,
