Trigonometry (10th Edition)

by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie

Published by Pearson

ISBN 10: 0321671775

ISBN 13: 978-0-32167-177-6

Appendix B - Graphs of Equations - Page 425: 41

Answer

Refer to Graph I, Center of the circle = $(3, 1)$ Radius = $\frac{5 – 1}{2}$ = $2$ The center-radius form of the circle equation is $(x – 3)^2$ + $(y – 1)^2$ = $4$

Work Step by Step

Refer to Graph I, Center of the circle = $(3, 1)$ Radius = $\frac{5 – 1}{2}$ = $2$ The center-radius form of the circle equation is $(x – 3)^2$ + $(y – 1)^2$ = $2^2$ $(x – 3)^2$ + $(y – 1)^2$ = $4$

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