Answer
Refer to Graph I,
Center of the circle = $(3, -3)$
Radius = $\frac{6 – 0}{2}$ = $3$
The center-radius form of the circle equation is
$(x – 3)^2$ + $(y – (-3))^2$ = $3^2$
$(x - 3)^2$ + $(y + 3)^2$ = $9$
Work Step by Step
Refer to Graph I,
Center of the circle = $(3, -3)$
Radius = $\frac{6 – 0}{2}$ = $3$
The center-radius form of the circle equation is
$(x – 3)^2$ + $(y – (-3))^2$ = $3^2$
$(x - 3)^2$ + $(y + 3)^2$ = $9$
