Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Appendix B - Graphs of Equations - Page 425: 42

Answer

Refer to Graph I, Center of the circle = $(-1, -2)$ Radius = $\frac{2 – (-4)}{2}$ = $3$ The center-radius form of the circle equation is $(x + 1)^2$ + $(y + 2)^2$ = $9$

Work Step by Step

Refer to Graph I, Center of the circle = $(-1, -2)$ Radius = $\frac{2 – (-4)}{2}$ = $3$ The center-radius form of the circle equation is $(x – (-1))^2$ + $(y – (-2))^2$ = $3^2$ $(x + 1)^2$ + $(y + 2)^2$ = $9$
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