Trigonometry (10th Edition)

by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie

Published by Pearson

ISBN 10: 0321671775

ISBN 13: 978-0-32167-177-6

Appendix B - Graphs of Equations - Page 425: 43

Answer

Refer to Graph I, Center of the circle = $(-2, 2)$ Radius = $\frac{0 – (-4)}{2}$ = $2$ The center-radius form of the circle equation is $(x + 2)^2$ + $(y - 2)^2$ = $4$

Work Step by Step

Refer to Graph I, Center of the circle = $(-2, 2)$ Radius = $\frac{0 – (-4)}{2}$ = $2$ The center-radius form of the circle equation is $(x – (-2))^2$ + $(y – 2)^2$ = $2^2$ $(x + 2)^2$ + $(y - 2)^2$ = $4$

Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.