Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 52: 21

Answer

$\cos$ 30$^{\circ}$ = $\sin$ 60$^{\circ}$

Work Step by Step

$\cos$ $A$ = $\sin$ (90$^{\circ}$ - $A$) Therefore: $\cos$ 90$^{\circ}$ = $\cos$ (90$^{\circ}$ - 30$^{\circ}$) = $\sin$ 60$^{\circ}$ Therefore: $\cos$ 30$^{\circ}$ = $\sin$ 60$^{\circ}$
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