Answer
$\sec$($\theta$ + 15$^{\circ}$) = $\csc$(75$^{\circ}$ - $\theta$ )
Work Step by Step
$\sec$($\theta$ + 15$^{\circ}$)
According to the Cofunction Identities
$\sec$$A$ = $\csc$(90$^{\circ}$ - $A$)
Therefore:
$\sec$($\theta$ + 15$^{\circ}$) = $\csc$(90$^{\circ}$ - 15$^{\circ}$ - $\theta$ )
$\sec$($\theta$ + 15$^{\circ}$) = $\csc$(75$^{\circ}$ - $\theta$ )