Answer
False
Work Step by Step
$\sin$ 30$^{\circ}$ + $\sin$ 60$^{\circ}$ = $\sin$(30$^{\circ}$ + 60$^{\circ}$)
$\sin$ 30$^{\circ}$ = $\frac{1}{2}$
$\sin$ 60$^{\circ}$ = $\frac{\sqrt3}{2}$
$\sin$ 30$^{\circ}$ + $\sin$ 60$^{\circ}$ = $\frac{1}{2}$ + $\frac{\sqrt3}{2}$
$\sin$ 30$^{\circ}$ + $\sin$ 60$^{\circ}$ = $\frac{1 + \sqrt3}{2}$
$\sin$(30$^{\circ}$ + 60$^{\circ}$) = $\sin$ 90$^{\circ}$
$\sin$ 90$^{\circ}$ = 1
Thus:
$\frac{1 + \sqrt3}{2}$ $\ne$ 1
Therefore, $\sin$ 30$^{\circ}$ + $\sin$ 60$^{\circ}$ = $\sin$(30$^{\circ}$ + 60$^{\circ}$) is a false statement.
