Answer
True
Work Step by Step
$\tan$$^{2}$ 60$^{\circ}$ + 1 = $\sec$$^{2}$ 60$^{\circ}$
First evaluate the value of each trigonometric statement:
$\tan$ 60$^{\circ}$ = $\sqrt3$
$\sec$ 60$^{\circ}$ = 2
Next evaluate each side of the equation:
$\tan$$^{2}$ 60$^{\circ}$ + 1 = ($\sqrt3$)$^{2}$ + 1
= 3 + 1
= 4
$\sec$$^{2}$ 60$^{\circ}$ = 2$^{2}$
= 4
Therefore:
$\tan$$^{2}$ 60$^{\circ}$ + 1 = $\sec$$^{2}$ 60$^{\circ}$ is a true statement.
