Answer
$x = \pm 4$
Work Step by Step
$\sin{\theta} = \dfrac{y}{r} = \dfrac{-3}{5}$
$\therefore y = -3 \hspace{20pt} r = 5$
$r^2 = x^2 + y^2 \\ x^2 = r^2 - y^2 \\ x = \pm \sqrt{r^2 - y^2} = \pm \sqrt{(5)^2-(-3)^2}$
$\boxed{x = \pm 4}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 1 - Section 1.3 - Definition I: Trigonometric Functions - 1.3 Problem Set - Page 33: 76
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