Answer
Chapter 2 - Section 2.3 Problem Set: 46 (Answer)
Refer to Figure I
$x = 47$ (To the nearest digit)
$h = 62$ (To the nearest digit)
Work Step by Step
Chapter 2 - Section 2.3 Problem Set: 46 (Solution)
Refer to Figure I
In $\triangle$ABC,
$\tan 48^{\circ} = \frac{x}{42}$
$x = 42 \cdot \tan 48^{\circ}$
$x = 47$ (To the nearest digit)
In $\triangle$DAB,
$\tan 53^{\circ} = \frac{h}{x}$
$\tan 53^{\circ} = \frac{h}{47}$
$h = 47 \cdot \tan 53^{\circ}$
$h = 62$ (To the nearest digit)
