Answer
Chapter 2 - Section 2.3 Problem Set: 50 (Answer)
Refer to Figure 1
$x = 8.0$ (To 2 significant digits)
$y = 6.4$ (To 2 significant digits)
Work Step by Step
Chapter 2 - Section 2.3 Problem Set: 50 (Solution)
Refer to Figure 1
In $\triangle$BDC,
$\cos\angle BDC$ = $\frac{x}{DB}$
$\cos 48^{\circ}$ = $\frac{x}{12}$
$x = 12 \cdot \cos 48^{\circ}$
$x = 8.0$ (To 2 significant digits)
In $\triangle$BAC,
$\cos A$ = $\frac{AC}{AB}$
$\cos 32^{\circ}$ = $\frac{(8.0+y)}{17}$
$8.0 + y = 17 \cdot \cos 32^{\circ}$
$y = 6.4$ (To 2 significant digits)
