Answer
Chapter 2 - Section 2.3 Problem Set: 52 (Answer)
Refer to Figure 1
$h = 30$ (To 2 significant digits)
$x = 27$ (To 2 significant digits)
Work Step by Step
Chapter 2 - Section 2.3 Problem Set: 52 (Solution)
Refer to Figure 1
In $\triangle$BAC,
$\sin A$ = $\frac{h}{AB}$
$\sin 32^{\circ}$ = $\frac{h}{56}$
$h = 56 \cdot \sin 32^{\circ}$
$h = 30$ (To 2 significant digits)
In $\triangle$BDC,
$\tan\angle BDC$ = $\frac{h}{x}$
$\tan 48^{\circ}$ = $\frac{30}{x}$
$x = \frac{30}{\tan 48^{\circ}}$
$x = 27$ (To 2 significant digits)
