Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Heat Transfer and Temperature Measurement - Page 39: 53

Answer

a) $518.15\, K$ b) $-247.95^{\circ}C$ c) $-43.6^{\circ}F$ d) $316.48\, K$

Work Step by Step

a) $245^{\circ} \, C=(245+273.15) \, K=518.15\,K$ b) $25.2\, K=(25.2-273.15)^{\circ} C=-247.95^{\circ}C$ c) $-42.0^{\circ}\, C=[(-42.0\times\frac{9}{5})+32]^{\circ}\,F$ $=-43.6^{\circ}F$ d) $110.0^{\circ}F=[(110.0-32)\times\frac{5}{9}]^{\circ}C$ $=43.33^{\circ}C=(43.33+273.15) K$ $=316.48\, K$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.