Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Heat Transfer and Temperature Measurement - Page 39: 54

Answer

a) $-9.4^{\circ}C$ b) $273.48\, K$ c) $130.7^{\circ}F$ d) $52.3^{\circ}F$

Work Step by Step

a) $15^{\circ}F=[(15-32)\frac{5}{9}]^{\circ}C=-9.4^{\circ}C$ b) $32.6^{\circ}F=[(32.6-32)\frac{5}{9}]^{\circ}C=0.333^{\circ}C$ $=(0.333+273.15) \, K=273.48\,K$ c) $328\, K=(328-273.15) ^{\circ}C$ $=54.85^{\circ}C=[(54.85\times\frac{9}{5})+32]^{\circ}F$ $=130.7^{\circ}F$ d) $11.3^{\circ}C=[(11.3\times\frac{9}{5}) +32]^{\circ}F$ $=52.3^{\circ}F$
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