Answer
$30.7\ kJ/min$
Work Step by Step
Calculate the mass of water:
$d=\frac mV$
$m=245\ mL\cdot 0.997\ g/mL=244.3\ g$
Calculate the heat required, in kJ, to raise the temperature of water ($c=4.184\ J/g.°C$) from 25.0°C to 85.0°C using the sensible heat equation:
$q=mc\Delta T$
$q=244.3\ g\cdot 4.184\ J/g.°C\cdot (85°C-25°C)\cdot \frac{1\ kJ}{10^3\ J}$
$q=61.3\ kJ$
Neglecting heat losses, calculate the thermal power required to provide this amount of heat in 2.00 min:
$P=\frac q{\Delta t}$
$P=61.3\ kJ\div 2.00\ min$
$P=30.7\ kJ/min$