Answer
3360 J
Work Step by Step
Heat $q=mc\Delta T$ where $m$ is the mass, $c$ is the specific heat and $\Delta T$ is the change in temperature.
That is, $q=(15.5\, g) (4.184\, J/g\cdot^{\circ}C) (38.2^{\circ}C-90.0^{\circ}C)$
$=-3360\, J$
Negative sign indicates that the heat is to be removed.
Therefore, heat to be removed= $3360\,J$
