Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 2 - Chemical Formulas and Composition Stoichiometrhy - Exercises - Determination of Simplest and Molecular Formulas - Page 76: 67

Answer

Simplest formula: $CH_4N$ Molecular formula: $C_2H_8N_2$

Work Step by Step

Step 1: Calculate the mass of carbon in $CO_2$ $4.839g~CO_2 \times \frac{12g~C}{44g~CO_2} = 1.31973g~Carbon$ Step 2: Calculate the mass of hydrogen in $H_2 O$ $3.959g~H_2O \times \frac{2g ~H}{18g~H_2O} = 0.439889g ~Hydrogen$ Step 3: Calculate the mass of nitrogen 3.302 - (1.31973 + 0.439889) = 1.5424g nitrogen Step 4: Calculate the moles of each element mole of Carbon: $\frac{1.31973}{12.01} = 0.10989 mole$ mole of Hydrogen: $\frac{0.439889}{1.007} = 0.43683 mole$ mole of nitrogen: $\frac{1.542381}{14.01} = 0.11009 mole$ Step 5: Divide by the smallest number of moles Ratio for carbon: $\frac{0.10989}{0.10989} = 1 $ Ratio for Hydrogen: $\frac{0.43683}{0.10989} = 4$ Ration of Nitrogen: $\frac{0.11017}{0.10989} = 1$ Simplest formula: $C H_4 N$ Step 6: Find the molecular formula Ratio of masses: $\frac{60.10}{30.05} = 2$ Multiply the simplest formula by 2 Molecular formula: $C_2H_8N_2$
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