Answer
$MgHSiO_4$
Work Step by Step
Step 1: Calculate the mass of Mg from MgO
$0.104g~MgO \times \frac{24.31g~Mg}{40.31g~MgO} = 0.06272g~of Mg$
Step 2: Calculate the mass of H from $H_2 O$
$0.0231g~ H_2O \times \frac{2.016g~H}{18.016g~H_2 O} = 0.00258g~of H$
Step 3: Calculate the mass of Si from $SiO_2$
$0.155g~SiO_2 \times \frac{28.09g~Si}{60.09g~SiO_2} = 0.07246g~of~Si$
Step 4: Calculate the mass of Oxygen
0.301g - (0.06272+0.00258+0.07246) = 0.16324 g of Oxygen
Step 5: Calculate the number of moles for each elements
$Mg = \frac{0.06272}{24.31} = 0.00258 mole$
$H = \frac{0.00258}{1.008} = 0.00258 mol$
$Si = \frac{0.07246}{28.09} = 0.00258 mol $
$O = \frac{0.16324}{16} = 0.0102 mol$
Step 6: Find the ratio
Mg = 0.00258/0.00258 = 1
H = 0.00258/0.00258 = 1
Si = 0.00258/0.00258 = 1
O = 0.0102/0.00258 = 4
$MgHSiO_4$
