Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 2 - Chemical Formulas and Composition Stoichiometrhy - Exercises - Determination of Simplest and Molecular Formulas - Page 76: 68

Answer

The maximum mass of carbon dioxide=$0.7216g$

Work Step by Step

The compound contains 2 carbon atoms that form a bond with 5 hydrogen atoms and a hydroxyl group(OH). So, this is ethanol $C_2H_5OH$ The number of moles can be calculated using the formula: Number of moles$=\frac{mass}{molecularmass}$ The number of moles of ethanol=$\frac{0.377}{46}=\approx0.0082mol$ In combustion reaction ethanol react with oxygen to form carbon dioxide and water by balanced chemical reaction: $2C_2H_5OH+6O_2\rightarrow 4CO_2+6H_2O$ According to the balanced chemical reaction, 2 moles of ethanol produced 4 moles of carbon dioxide. So, 0.0082mol of ethanol will produce: $0.0082mol-ethanol\times\frac{4mol-carbondioxde}{2mol-ethanol}=0.0164mol-carbon dioxide$ Finally, we can calculate the mass of carbon dioxide using the formula: mass of carbon dioxide=$molar mass\times number of moles=44\times 0.0164=0.7216g$
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