Answer
$C_2 H_6 O$
Work Step by Step
Step 1: Calculate the mass of C from $CO_2$
$1.913g~CO_2 \times \frac{12.01g~C}{44.01g~CO_2} = 0.52204g~C$
Step 2: Calculate the mass of H from $H_2O$
$1.174g~H_2O \times \frac{2.016g~H}{18.016g~H_2O} = 0.13137g~H$
Step 3: Calculate the mass of oxygen
1.00grams - (0.52204 + 0.13137) = 0.34659g of oxygen
Step 4: Calculate the number of moles
$C = \frac{0.52204}{12.01} = 0.0435 mole$
$H = \frac{0.13137}{1.008} = 0.13033 mole$
$O = \frac{0.34659}{16} = 0.02166 mole$
Step 5: Find the ratio by dividing by the smallest number of moles
C = 0.0435/0.0216 = 2
H = 0.13033/0.0216 = 6
O = 0.0216/0.0216 = 1
Simplest formula $C_2H_6O$
