Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 3 - Chemical Equations and Reaction of Stoichiometry - Exercises - Percent Yield from Chemical Reactions - Page 109: 40

Answer

113.1 g PCl5

Work Step by Step

Theoretical yield: Find the moles of PCl3 from the grams of PCl3 by dividing by its atomic mass. 92.5g/ 137.32g/mol = 0.71 mol PCl3 Find the moles of PCl5 produced from the PCl3 by multiplying by the molar ratio. 0.71 mol PCl3 x (1 mol PCl5/1 mol PCl3) = 0.71 mol PCl5 Find the number of grams of PCl5 by multiplying the moles of PCl5 by the molar mass. 0.71 mol PCl5 x 208.22g/mol = 147.84 g PCl5 Actual yield = Theoretical Yield x (Percent yield/100) = 147.84 g x 0.765 = 113.1 g PCl5
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