Answer
a. 0.0462 mol BrCl
b. 0.0119 mol Br2
Work Step by Step
a. Theoretical yield: Use either of the reactants to determine the number of moles of BrCl produced. Multiply the moles of Br2 by the molar ratio:
0.0350 mol Br2 x (2 mol BrCl/1 mol Br2) = 0.070 mol BrCl
Actual yield = Theoretical Yield x (Percent yield/100)
= 0.070mol x 0.660 = 0.0462 mol BrCl
b. Find the amount of Br2 consumed to produce 0.0462 moles of BrCl. Multiply the moles of BrCl by the molar ratio.
0.0462 mol BrCl x (1 mol Br2/2 mol BrCl2) = 0.0231 mol Br2
Excess Br2 = given Br2-consumed Br2
= 0.0350 mol - 0.0231 mol = 0.0119 mol Br2 unchanged
