Answer
[H3O+] = $10^{-11}$
[OH-] = $10^{-3}$
Work Step by Step
The H3O concentration is equal to $10^{-pH}$
The OH- concentration is equal to $10^{-pOH}$, or $10^{-(14-pH)}$
$[H3O+] = 10^{-11}$
$[OH-] = 10^{-(14-11)}$
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