Answer
There are necessary 48.0 mL of that $NaOH$ solution to completely neutralize that $HCl$.
Work Step by Step
1. Write and balance the equation for the reaction:
$NaOH + HCl -- \gt NaCl + H_2O$
** The equation is already balanced.
2. Use the given information as conversion factors to calculate the necessary volume.
- The concentration of this HCl solution is equal to $0.288$ mol in 1 L.
- The concentration of this NaOH solution is equal to $0.150$ mol in 1 L.
- Each mol of $NaOH$ reacts with 1 mol of $HCl$.
$25.0mL(HCl) \times \frac{1L}{1000mL} \times \frac{0.288mol(HCl)}{1L(HCl)} \times \frac{1 mol -NaOH}{1mol-HCl} \times \frac{1L(NaOH)}{0.150mol(NaOH)} \times \frac{1000mL}{1L} = 48.0 mL (NaOH)$
