Answer
The maximum height is 32 meters and the time in the air is 5.2 seconds.
Work Step by Step
(a) $y = \frac{v^2 - v_0^2}{2g} = \frac{-25^2}{2\times(-9.8)} = 31.89\approx32~m$
(b) The time $t$ to reach the maximum height is:
$t = \frac{v-v_0}{g} = \frac{-25}{-9.8} = 2.55\approx2.6~s$
The total time in the air is $2t$ which is 5.2 seconds.
(c) The ball is hit "almost" straight up in the air, so the vertical component of velocity is actually less than 25 m/s.
We are ignoring the air resistance.
The ball is hit at a height slightly off the ground, but we assume that the ball starts its flight from the level of the ground. For these reasons, our results are estimates.
