Answer
a. $t \approx 49 s$
b. t = 88s to t = 108s
c. 0s-44s, 55s-82s, and 88s-108s
d. 55s-82s
Work Step by Step
You may obtain slightly different answers depending on how you read the graph.
a. The greatest velocity is at the highest point on the graph. This happens at $t \approx 49 s$.
b. Periods of constant velocity, on a velocity-time graph, are indicated by horizontal segments (acceleration of 0, i.e., slope of zero). This occurs once, from t = 88s to t = 108s.
c. Periods of constant acceleration on a velocity-time graph are indicated by constant slope. This happens 3 times: from 0s-44s, 55s-82s, and from 88s-108s.
d. The magnitude of the acceleration is greatest on a v-t graph when the magnitude of the slope is the greatest. This occurs from 55s-82s.
