Answer
t = 1.09 seconds
Work Step by Step
To find the time to fall from a height of 1.45 meters, we can use this equation: $y = \frac{1}{2}at^2$.
We will rearrange the equation to make $t$ the subject of the equation and then solve:
$t^2 = \frac{2y}{a} = \frac{2\times1.45}{9.80} = 0.296$
$t = \sqrt{0.296} = 0.544 ~s$
The time to jump up and fall back down to the ground is double the time it takes to fall.
$t_{total} = 2\times0.544 = 1.09 ~s$
Therefore, the total time is 1.09 seconds.
