Answer
The distance traveled in each successive second is:
first second: $1\times4.90 ~meters$
second second: $3\times4.90 ~meters$
third second: $5\times4.90 ~meters$
fourth second: $7\times4.90 ~meters$
etc...
Work Step by Step
$v = v_0 + at$
$v_0 = 0 ~m/s$
$v_1 = 1\times9.80 ~m/s$
$v_2 = 2\times9.80 ~m/s$
$v_3 = 3\times9.80 ~m/s$
$v_4 = 4\times9.80 ~m/s$
etc...
The average velocity for each successive second is:
first second: $v_{ave} = \frac{v_0+v_1}{2} = 1\times4.9 ~m/s$
second second: $v_{ave} = \frac{v_1+v_2}{2} = 3\times4.9 ~m/s$
third second: $v_{ave} = \frac{v_2+v_3}{2} = 5\times4.9 ~m/s$
fourth second: $v_{ave} = \frac{v_3+v_4}{2} = 7\times4.9 ~m/s$
etc...
The distance traveled in each successive second is the average velocity multiplied by 1 second.
first second: $\Delta x = 1\times4.9 ~m$
second second: $\Delta x = 3\times4.9 ~m$
third second: $\Delta x = 5\times4.9 ~m$
fourth second: $\Delta x = 7\times4.9 ~m$
etc...
