Answer
See answers.
Work Step by Step
Let downward be the positive direction, and y = 0 to be the initial height.
a. The initial velocity is 0 and the speed is given by equation 2-11 with an acceleration of $9.8\; m/s^2$. As shown, the graph is a straight line passing through the origin with a slope of $9.8\; m/s^2$.
b. The distance fallen will be given by Eq. 2–11b with an acceleration of $9.8\; m/s^2$. As shown, the graph is a parabola, with its vertex at the origin.