Answer
$\frac{3ax^2}{(a^2-x)(a-x)}$
Work Step by Step
$\frac{(\frac{3a}{\frac{a^2}{x}-1})}{(\frac{a}{x}-1)}=\frac{(\frac{3a}{\frac{a^2-x}{x}})}{(\frac{a-x}{x})}=\frac{(3a)}{(\frac{a^2-x}{x})(\frac{a-x}{x})}=$$\frac{3ax^2}{(a^2-x)(a-x)}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Review Exercises - Page 64: 101
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