Answer
$\frac{x^2-3x+9}{x-2}, x\ne2, x\ne-3$
Work Step by Step
$\frac{x^3+27}{x^2+x-6}=\frac{(x+3)(x^2-3x+9)}{(x+3)(x-2)}=$$\frac{x^2-3x+9}{x-2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Review Exercises - Page 64: 96
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