Answer
$\frac{-1}{(x-3)(x+h-3)}$
Work Step by Step
$\frac{\frac{1}{x+h-3}-\frac{1}{x-3}}{h}=\frac{x-3-(x+h-3)}{h(x-3)(x+h-3)}=\frac{-h}{h(x-3)(x+h-3)}=\frac{-1}{(x-3)(x+h-3)}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Review Exercises - Page 64: 104
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